Basic Combination of Class C and Class B – Advance LAB

In this lab, I will show you the Basic Combination of Class C and Class B on 2 Routers

VLSM

Given Network: 192.168.0.0

Host Requirement on Router 1: 4000

Host Requirement on Router 2: 2048

Router 1<= 4000

4000<= 2ⁿ – 2

4000<= 2¹² – 2

4000<= 4096 – 2

4000<= 4094

Total number of network bit = 32

32 – n = 32 – 12 = 20 (CIDR of Router 1 network i.e. Given network)

i.e. 192.168.0.0/20

N.S.M = 11111111.11111111.11110000.00000000

                        = 255.255.240.0

Block Size        = 256 – N.S.M

                        = 256 – 240 = 16

Note: Add this block size in given network so that we can get our new network for Router 2.

so the new network is 192.168.16.0/?

Now find FVH, LVH and Broadcast address

Given Network	192	168	0	0
First Valid Host-FVH	192	168	0	1
Last Valid Host-LVH	192	168	15	254
Broadcast	192	168	15	255
New Network	192	168	16	0

Router 2<= 2048

2000 <= 2ⁿ – 2

2000 <= 2¹¹ – 2

2000 <= 2048 – 2

2000 <= 2046

Total number of network bits = 32

32 – n = 32 – 11 = 21 (CIDR of Router 2 network i.e. New network)

i.e. 192.168.16.0/21

N.S.M = 11111111.11111111.11111000.00000000

                        = 255.255.248.0

Block Size        = 256 – N.S.M

                        = 256 – 248 = 8

Note: Add this block size in given network so that we can get our new network for Router 1 and 2 (Virtual Network).

so the new network is 192.168.24.0?

Now find FVH, LVH and Broadcast address

Given Network	192	168	16	0
First Valid Host-FVH	192	168	16	1
Last Valid Host-LVH	192	168	23	254
Broadcast	192	168	23	255
New Network	192	168	24	0

Router 1 and Router 2 <= 2 (we required only two IP to connect two routers)

2 <= 2ⁿ – 2

2 <= 2² – 2

2 <= 4 – 2

2 <= 2

Total number of network bits = 32

32 – n = 32 – 2 = 30 (CIDR of Virtual network (R1&R2))

i.e. 192.168.24.0/30

N.S.M = 11111111.11111111.11111111.11111100

                        = 255.255.255.252

Block Size        = 256 – N.S.M

                        = 256 – 252 = 4

Note: Add this block size in given network so that we can get our new network for Router 3. This network can be used in future.

so the new network is 192.168.24.4/?

Now find FVH, LVH and Broadcast address

Given Network	192	168	24	0
First Valid Host-FVH	192	168	24	1
Last Valid Host-LVH	192	168	24	2
Broadcast	192	168	24	3
New Network	192	168	24	4

Basic Configuration on Router 1

Router>enable Router#configure terminal Router(config)#hostname R1 R1(config)#interface fastEthernet 0/0 R1(config-if)#ip address 192.168.0.1 255.255.240.0 R1(config-if)#no shutdown R1(config-if)#exit   R1(config)#interface serial 0/0/0 R1(config-if)#ip address 192.168.24.1 255.255.255.252 R1(config-if)#clock rate 64000 R1(config-if)#no shutdown R1(config-if)#exit R1(config)#exit R1#write

Basic Configuration on Router 2

Router>enable Router#configure terminal Router(config)#hostname R2 R2(config)#interface fastEthernet 0/0 R2(config-if)#ip  address 192.168.16.1 255.255.248.0 R2(config-if)#no shutdown R2(config-if)#exit   R2(config)#interface serial 0/1/0 R2(config-if)#ip address 192.168.24.2 255.255.255.252 R2(config-if)#no shutdown R2(config-if)#exit R2(config)#exit R2#write

Verification on Router 1

R1#show ip route   C    192.168.0.0/20 is directly connected, FastEthernet0/0      192.168.24.0/30 is subnetted, 1 subnets C       192.168.24.0 is directly connected, Serial0/0/0

Verification on Router 2

R2#show ip route   C    192.168.16.0/21 is directly connected, FastEthernet0/0      192.168.24.0/30 is subnetted, 1 subnets C       192.168.24.0 is directly connected, Serial0/1/0