Basic Combination of Class C and Class A – Advance LAB

In this lab, I will show you the Basic Combination of Class C and Class A on 2 Routers

VLSM

Given Network: 207.0.0.0

Host Requirement on Router 1: 500,000

Host Requirement on Router 2: 250,000

Router 1<= 500,000

500,000<= 2ⁿ – 2

500,000<= 2¹⁹ – 2

500,000<= 524,288 – 2

500,000<= 524,286

Total number of network bit = 32

32 – n = 32 – 19 = 13 (CIDR of Router 1 network i.e. Given network)

i.e. 207.0.0.0/13

N.S.M = 11111111.11111000.00000000.00000000

                        = 255.248.0.0

Block Size        = 256 – N.S.M

                        = 256 – 248 = 8

Note: Add this block size in given network so that we can get our new network for Router 2.

so the new network is 207.8.0.0/?

Now find FVH, LVH and Broadcast address

Given Network	207	0	0	0
First Valid Host-FVH	207	0	0	1
Last Valid Host-LVH	207	7	255	254
Broadcast	207	7	255	255
New Network	207	8	0	0

Router 2<= 250,000

250,000 <= 2ⁿ – 2

250,000<= 2¹⁸ – 2

250,000<= 262,144 – 2

250,000<= 262,142

Total number of network bits = 32

32 – n = 32 – 18 = 14 (CIDR of Router 2 network i.e. New network)

i.e. 207.8.0.0/14

N.S.M = 11111111.11111100.00000000.00000000

                        = 255.252.0.0

Block Size        = 256 – N.S.M

                        = 256 – 252 = 4

Note: Add this block size in given network so that we can get our new network for Router 1 and 2 (Virtual Network).

so the new network is 207.12.0.0/?

Now find FVH, LVH and Broadcast address

Given Network	207	8	0	0
First Valid Host-FVH	207	8	0	1
Last Valid Host-LVH	207	11	255	254
Broadcast	207	11	255	255
New Network	207	12	0	0

Router 1 and Router 2 <= 2 (we required only two IP to connect two routers)

2 <= 2ⁿ – 2

2 <= 2² – 2

2 <= 4 – 2

2 <= 2

Total number of network bits = 32

32 – n = 32 – 2 = 30 (CIDR of Virtual network (R1&R2))

i.e. 207.12.0.0/30

N.S.M = 11111111.11111111.11111111.11111100

                        = 255.255.255.252

Block Size        = 256 – N.S.M

                        = 256 – 252 = 4

Note: Add this block size in given network so that we can get our new network for Router 3. This network can be used in future.

so the new network is 207.12.0.4/?

Now find FVH, LVH and Broadcast address

Given Network	207	12	0	0
First Valid Host-FVH	207	12	0	1
Last Valid Host-LVH	207	12	0	2
Broadcast	207	12	0	3
New Network	207	12	0	4

Basic Configuration on Router 1

Router>enable Router#configure terminal Router(config)#hostname R1 R1(config)#interface fastEthernet 0/0 R1(config-if)#ip address 207.0.0.1 255.248.0.0 R1(config-if)#no shutdown R1(config-if)#exit   R1(config)#interface serial 0/0/0 R1(config-if)#ip address 207.12.0.1 255.255.255.252 R1(config-if)#clock rate 64000 R1(config-if)#no shutdown R1(config-if)#exit R1(config)#exit R1#write

Basic Configuration on Router 2

Router>enable Router#configure terminal Router(config)#hostname R2 R2(config)#interface fastEthernet 0/0 R2(config-if)#ip address 207.8.0.1 255.252.0.0 R2(config-if)#no shutdown R2(config-if)#exit   R2(config)#interface serial 0/1/0 R2(config-if)#ip address 207.12.0.2 255.255.255.252 R2(config-if)#no shutdown R2(config-if)#exit R2(config)#exit R2#write

Verification on Router 1

R1#show ip route C    207.0.0.0/13 is directly connected, FastEthernet0/0      207.12.0.0/30 is subnetted, 1 subnets C       207.12.0.0 is directly connected, Serial0/0/0

Verification on Router 2

R2#show ip route C    207.8.0.0/14 is directly connected, FastEthernet0/0      207.12.0.0/30 is subnetted, 1 subnets C       207.12.0.0 is directly connected, Serial0/1/0