Basic Router Configuration On Cisco Packet Tracer

How to configure a Cisco router

In this lab, I am gonna teach you Basic Router Configuration On Cisco Packet Tracer

Basic Router Configuration VLSM

Given network: 200.150.100.0

Required hosts on Router 1: 14

Required hosts on Router 2: 6

Basic Router Configuration On Cisco Packet  Tracer

R1<= 14

14<= 2n – 2

14<= 24 – 2

14<= 16 – 2

14<= 14

Total number of network bits = 32

32 – n = 32 – 4 = 28 (CIDR value of given network i.e. Router 1)

i.e. 200.150.100.0/28

N.S.M = 11111111. 11111111. 11111111.11110000

                        = 255.255.255.240

Block size        = 256 – N.S.M

                        = 256 – 240 = 16

Note: Add this block size in given network so that we can get our new network for Router 2.

So the new network is 200.150.100.16/?

Now find FVH, LVH, and broadcast address

Given Network2001501000
First Valid Host-FVH2001501001
Last Valid Host-LVH20015010014
Broadcast20015010015
New Network20015010016

R2<= 6

6<= 2n – 2

6<= 23 – 2

6<= 8 – 2

6<= 6

Total number of network bits = 32

32 – n = 32 – 3 = 29 (CIDR value of new network i.e. Router 2)

i.e. 200.150.100.16/29

N.S.M = 11111111. 11111111. 11111111.11111000

                        = 255.255.255.248

Block size        = 256 – N.S.M

                        = 256 – 248 = 8

Note: Add this block size in given network so that we can get our new network for Router 1 and 2 (Virtual Network).

So the new network is 200.150.100.24/?

Now find FVH, LVH, and broadcast address

Given Network20015010016
First Valid Host-FVH20015010017
Last Valid Host-LVH20015010022
Broadcast20015010023
New Network20015010024

Router 1 & 2 <= 2 hosts (we required only two IP to connect 2 routers)

2 <= 2n – 2

2 <= 22 – 2

2 <= 4 – 2

2 <= 2

Total number of network bits = 32

32 – n = 32 – 2 = 30 (CIDR of Virtual network (R1&R2)

i.e. 200.150.100.24/30

N.S.M = 11111111.11111111.11111111.11111100

= 255.255.255.252

Block Size        = 256 – N.S.M

= 256 – 252 = 4

Note: Add this block size in given network so that we can get our new network for Router 3. This network can be used in future.

so the new network is 200.150.100.28/?

Now find FVH, LVH and Broadcast address

Given Network20015010024
First Valid Host-FVH20015010025
Last Valid Host-LVH20015010026
Broadcast20015010027
New Network20015010028

Class A, Class B, Class C, Master in Networking, all e-books – Combo offer- 50% off.

Basic Router Configuration on Router 1

Router>enable
Router#configure terminal
Router(config)#hostname R1
R1(config)#interface fastEthernet 0/0
R1(config-if)#ip address 200.150.100.1         255.255.255.240
R1(config-if)#no shutdown
R1(config-if)#exit  

R1(config)#interface serial 0/0/0
R1(config-if)#ip address 200.150.100.25       255.255.255.252
R1(config-if)#clock rate 64000
R1(config-if)#no shutdown
R1(config-if)#exit
R1(config)#exit R1#write

Basic Router Configuration on Router 2

Router>enable
Router#configure terminal
Router(config)#hostname R2
R2(config)#interface fastEthernet 0/0
R2(config-if)#ip address 200.150.100.17       255.255.255.248
R2(config-if)#no shutdown
R2(config-if)#exit  

R2(config)#interface serial 0/1/0
R2(config-if)#ip address 200.150.100.26       255.255.255.252
R2(config-if)#no shutdown
R2(config-if)#exit
R2(config)#exit
R2#write

Verification on Router 1

R1#show ip route     
200.150.100.0/24 is variably subnetted, 2 subnets, 2 masks
C       200.150.100.0/28 is directly connected, FastEthernet0/0
C       200.150.100.24/30 is directly connected, Serial0/0/0

Verification on Router 2

R2#show ip route     
200.150.100.0/24 is variably subnetted, 2 subnets, 2 masks
C       200.150.100.16/29 is directly connected, FastEthernet0/0
C       200.150.100.24/30 is directly connected, Serial0/1/0
Basic Router Configuration On Cisco Packet  Tracer

If you like our LABs, you can support us by donating just $1. It will really encourage us. EIHeducation


Leave a Reply

Your email address will not be published.